Question

k⃗⋅k⃗=

  1. 1
  2. 0
  3. 2
  4. -1

Answer: 1

Solution :-

We know that i⃗,j⃗andk⃗ are unit vector in the direction of x,yandz−a⁢x⁢i⁢s respectively.
Hence, ∣i⃗∣=∣j⃗∣=∣k⃗∣=1⋅

And, also We know that the angle between any position vector with itself is 0.

So,k⃗⋅k⃗=∣k⃗∣⋅∣k⃗∣⋅cos0=1⋅1⋅1(∵∣k⃗∣=1andcos0=1)=1⋅

So, correct answer is option-1, →1