Question

$∣ 2 \vec{i} - 3 \vec{j} + \vec{k} ∣ =$

Answer: $\sqrt{14}$

\begin{aligned} ∣ 2 \vec{i} - 3 \vec{j} + \vec{k} ∣ & = & \sqrt{{(2)}^{2} + {(- 3)}^{2} + {(1)}^{2}} \\ = & \sqrt{4 + 9 + 1} \\ = & \sqrt{14} \cdot \end{aligned}

So, correct answer is option-2, $\to \sqrt{14}$