Question

IfOA=2i+5j2kandOB=3i+6j+5kthenAB=

  1. i+j+7k
  2. 5i+2j+k
  3. i+2j7k
  4. ijk

Answer: i+j+7k

Solution :-

Given that OA=2i+5j2kandOB=3i+6j+5k , then

AB=OBOA(Because,OB>OA)=(3i+6j+5k)(2i+5j2k)=3i+6j+5k2i5j+2k=(32)i+(65)j+(5+2)k=i+j+7k

So, correct answer is option-1, i+j+7k