Question

If S be the sample space and E be the event then P (E) = __________

  1. n(E)n(S)
  2. n(S)n(E)
  3. n(E)
  4. n(S)

Answer: n(E)n(S)

Solution :-

Probability of an event : Let S be a sample space and E be an event, such that n(S) = n and n(E) = m.

If each outcomes is equally likely, then it follows that

P(E)=mn=(number of outcomes favourable to E)Total possible outcomes=n(E)n(S)

So, correct answer is option-1, n(E)n(S)