Question

$If | \begin{array}{cccccccccc} x & 5 \\ 5 & x \end{array} | = 0 then x =__________$

\begin{array}{l} \begin{array}{rcl} Given that | \begin{array}{cccccccccc} x & 5 \\ 5 & x \end{array} | & = & 0 \\ then, x^{2} - 5^{2} & = & 0 (after determinant) \\ s o, x^{2} & = & 25 \\ ∴ x & = & \pm 5 \end{array} \end{array}

So, correct answer is option-1, $\to \pm 5$