Question

$| \begin{array}{cccccccccc} 10 & 2 \\ 35 & 7 \end{array} | =__________$

\begin{array}{l} \begin{array}{rcl} | \begin{array}{cccccccccc} 10 & 2 \\ 35 & 7 \end{array} | & = & (10 \times 7) - (2 \times 35) (after determinant) \\ = & 70 - 70 \\ = & 0 \end{array} \end{array}

So, correct answer is option-2, $\to 0$