Question

dd⁢x⁢(tana⁢x) =

  1. atana⁢x
  2. asec2a⁢x
  3. asecx
  4. acota⁢x

Answer: asec2a⁢x

Solution :-

dd⁢x⁢(tana⁢x)=d⁢(tan(a⁢x))d⁢(a⁢x)×d⁢(a⁢x)d⁢x=sec2(a⁢x)×d⁢(a⁢x)d⁢x (∵derivative oftanxis sec2x)=sec2(a⁢x)×a×d⁢(x)d⁢x(∵’a’ is constant)=sec2(a⁢x)×a×1=asec2(a⁢x)⋅

So, correct answer is option-2, →asec2a⁢x