Question

ddx(tanax) =

  1. atanax
  2. asec2ax
  3. asecx
  4. acotax

Answer: asec2ax

Solution :-

ddx(tanax)=d(tan(ax))d(ax)×d(ax)dx=sec2(ax)×d(ax)dx (derivative oftanxis sec2x)=sec2(ax)×a×d(x)dx(’a’ is constant)=sec2(ax)×a×1=asec2(ax)

So, correct answer is option-2, asec2ax